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The "flavor show" command could not show a private flavor by flavor name becauce it could not find a private flavor by flavor name. In "until.find_resource(parsed_args.flavor)", If parsed_args.falvor is a name of a flavor, "flavors.find(name=parsed_args.flavor)"will be called to find a flavor.But the default value of "is_public" is "Ture" in "flavors.find()" so that we can only find public flavors.If we want to find all flaovrs by flavor name,we should add "is_public=None" in "flavors.find()". So I tried to change "until.find_resource(parsed_args.flavor)" to "until.find_resource(parsed_args.flavor, is_public=None)", but then I could not find any flavor by flavor id because "is_public" is an unexpected argument of "flavors.get()" in "until.find_resource()". In this case,I think "until.find_resource()" can not find a private flavor properly,and we should combine "manager.get(flavor.id)" and "manager.find(name=flavor.name, is_public=None)" by ourselve to find a flavor. Also,this bug affects other flavor commands like "flavor set/unset/delete",so I fix them in this patch too. Change-Id: I4a4ed7b0a2f522ee04d1c3270afcda7064285c39 Closes-Bug: #1575478 |
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| .. | ||
| api | ||
| common | ||
| compute | ||
| identity | ||
| image | ||
| locale | ||
| network | ||
| object | ||
| tests | ||
| volume | ||
| __init__.py | ||
| i18n.py | ||
| shell.py | ||